If `A=(a_(i j))_(nxxn)` and `f` is a function, we define `f(A)=((f(a_(i j))))_(nxxn ')` Let `A=([pi//2-theta,theta],[-theta,pi//2-theta])` . Then

Let A=sin^8theta+cos^14theta, " then "A_("max") is

Range of f(theta)=cos^2theta(cos^2theta+1)+2sin^2theta is

If f (theta) = |sin theta| + |cos theta|, theta in R , then

The range of the function f (theta) =(sin theta)/( theta ) + (theta)/(tan theta) , theta in (0, (pi)/(2)) is equal to :

If A=[a_(i j)] is a 2xx2 matrix such that a_(i j)=i+2j , write A .

For all theta, sin theta + sin(theta + pi)+sin (2pi + theta)=

If f(theta)=|(cos^(2)theta ,cos theta sin theta, -sin theta),(cos theta sin theta, sin^(2)theta,cos theta),(sin theta,-cos theta,0)| then, f((pi)/(6))+f((pi)/(3))+f((pi)/(2))+f((2pi)/(3))+f((5pi)/(6))+f(pi)+……+f((53pi)/(6)) is equal to

If A=([a_(i j)])_(nxxn) is such that ( a )_(i j)=bar (a_(j i)),AAi ,j and A^2=O , then Statement 1: Matrix A null matrix. Statement 2: |A|=0.

Prove that (cos(pi +theta)cos (-theta))/(cos(pi-theta) cos (pi/2+theta))=-cot theta

If f(x) is an integrable function on [(pi)/(6),(pi)/(3)] and I_(1)=int_(pi//6)^(pi//3) sec^(2)thetaf(2 sin 2theta)d theta" and "I_(2)=int_(pi//6)^(pi//3) "cosec"^(2)theta f(2 sin2theta)d theta , then