If `y(x)` satisfies the differential equation `y^(prime)-ytanx=2xs e c x` and `y(0)=0` , then

If y(x) satisfies the differential equation y'-y tan x=2x and y(0)=0 , then

Solve the differential equation: y\ dx+(x-y^2)dy=0

If y(t) satisfies the differential equation y'(t)+2y(t)=2e^(-2t),y(0)=2 then y(1) equals

Solve the differential equation y e^(x/y)dx=(x e^(x/y)+y^2)dy(y!=0)

Solve the differential equation y e^(x/y)dx=(x e^(x/y)+y^2siny)dy(y!=0)

The solution to the differential equation ylogy+x y^(prime)=0, where y(1)=e , is

Let y(x) be a solution of the differential equation (1+e^x)y^(prime)+y e^x=1. If y(0)=2 , then which of the following statements is (are) true? (a) y(-4)=0 (b) y(-2)=0 (c) y(x) has a critical point in the interval (-1,0) (d) y(x) has no critical point in the interval (-1,0)

If y(x) satisfies the differential equation (dy)/(dx)=(x^2-2y)/x where y(1)=-2 then y(x) will pass through the poing (A) (0,sqrt3) (B) (3,0) (C) (sqrt3,0) (D) (0,3)

Solve the differential equation (x y^2+x)dx+(y x^2+y)dy=0

If K is constant such that xy + k = e ^(((x-1)^2)/(2)) satisfies the differential equation x . ( dy )/( dx) = (( x^2 - x-1) y+ (x-1) and y (1) =0 then find the value of K .