For the primitive integral equation y dx...

For the primitive integral equation `y dx+y^2dy=xdy ; x in R ,y >0,y(1)=1,` then `y(-3)` is (a) 3 (b) 2 (c) 1 (d) 5

AI Generated Solution

Similar Questions

Explore conceptually related problems

The solution of the primitive integral equation (x^2+y^2)dy=x ydx is y=y(x)dot If y(1)=1 and y(x_0)=e , then x_0 is

Consider the differential equation y^2dx+(x-1/y)dy=0 if y(1)=1 then x is

If xdy=ydx+y^2dy and y(1)=1 , then y(-3) is equal to (A) 1 (B) 5 (C) 4 (D) 3

If sin(x+y)=log(x+y) , then (dy)/(dx)= (a) 2 (b) -2 (c) 1 (d) -1

Solve the differential equation: (1+y+x^2y)dx+(x+x^3)dy=0

Solve the differential equation x(d^2y)/dx^2=1 , given that y=1, (dy)/(dx)=0 when x=1

For y gt 0 and x in R, ydx + y^(2)dy = xdy where y = f(x). If f(1)=1, then the value of f(-3) is

xdy-ydx = 2x^(3)y(xdy+ydx) if y(1) = 1, then y(2) +y((1)/(2)) =

The solution of differential equation (d^2y)/(dx^2)=dy/dx,y(0)=3 and y'(0)=2 :

The general solution of the differential equation (y dx-x dy)/y=0 is(A) x y = C (B) x=C y^2 (C) y = C x (D) y=C x^2