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Spherical rain drop evaporates at a rate...

Spherical rain drop evaporates at a rate proportional to its surface area. The differential equation corresponding to the rate of change of the radius of the rain drop if the constant of proportionality is `K >0` is

A

`(dr)/(dt)+ K=0`

B

`(dr)/(dt) -K =0`

C

`(dr)/(dt) = Kr`

D

None of these

Text Solution

AI Generated Solution

To derive the differential equation corresponding to the rate of change of the radius of a spherical raindrop that evaporates at a rate proportional to its surface area, we can follow these steps: ### Step 1: Understand the volume and surface area of a sphere The volume \( V \) of a spherical raindrop with radius \( r \) is given by: \[ V = \frac{4}{3} \pi r^3 \] The surface area \( S \) of the spherical raindrop is given by: ...
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