Find the distance between the pair of parallel lines `x^2+4x y+4y^2+3x+6y-4=0`

Explanation

To find the distance between the pair of parallel lines given by the equation \( x^2 + 4xy + 4y^2 + 3x + 6y - 4 = 0 \), we will follow these steps:

### Step 1: Rewrite the equation
We start with the given equation:
\[ x^2 + 4xy + 4y^2 + 3x + 6y - 4 = 0 \]
We can group the terms to factor the quadratic in \(x\) and \(y\):
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