A triangle ABC with vertices A(-1,0),B(-2,3/4) & C(-3,-7/6) has its orthocentre H, then the orthocentre of triangle BCH will be

Let k be an integer such that the triangle with vertices (k ,-3k),(5, k) and (-k ,2) has area 28s qdot units. Then the orthocentre of this triangle is at the point : (1) (1,-3/4) (2) (2,1/2) (3) (2,-1/2) (4) (1,3/4)

Statement-1: The orthocentre of the triangle having its verticews at A(2,0), B(4,0) and C(4,6) is at the point o(4,0) Statement-2 : Orthocentre of a right triangle is at the vertex forming a right angle

Two vertices of a triangle are (3,-2) and (-2,3) and its orthocentre is (-6,1) . Then the third vertex of this triangle can not lie on the line

If two vertices of a triangle are (0,2) and (4,3) and its orthocentre is (0,0) then the third vertex of the triangle lies in (a) 1^(st) quadrant (b) 2^(nd) quadrant (c) 3^(rd) quadrant (d) 4^(th) quadrant

If two vertices of a triangle are (0,2) and (4,3) and its orthocentre is (0,0) then the third vertex of the triangle lies in (a) 1^(st) quadrant (b) 2^(nd) quadrant (c) 3^(rd) quadrant (d) 4^(th) quadrant

If two vertices of a triangle are (0,2) and (4,3) and its orthocentre is (0,0) then the third vertex of the triangle lies in (a) I^(st) quadrant (b) 2^(nd)quadrant (c) 3^(rd)quadrant (d) 4^(th)quadrant

Find the coordinates of the orthocentre of a triangle whose vertices are (-1, 3) (2,-1) and (0, 0). [Orthocentre is the point of concurrency of three altitudes].

Show that (-1/2,2,0) is the circumacentre of the triangle whose vertices are A (1, 1, 0),B(1, 2, 1) and C (-2, 2, -1) and hence find its orthocentre.

The triangle ABC, where A is (2, 6), B is (-3, 5) and C is (4, 7), is reflected in the y-axis to triangle A'B'C'. Triangle A'B'C' is then reflected in the origin to triangle A"B"C''. Write down a single transformation that maps triangle ABC onto triangle A"B"C".

Orthocentre of triangle whose vertices are (0, 0), (3, 4), (4, 0) is