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Consider three points P = (-sin (beta-al...

Consider three points `P = (-sin (beta-alpha), -cos beta)`, `Q = (cos(beta-alpha), sin beta)`, and `R = ((cos (beta - alpha + theta), sin (beta - theta))`, where `0< alpha, beta, theta < pi/4` Then

A

P lies on the line segment RQ

B

Q lies on the segment PR

C

R lies on the line segment PR

D

P,Q,R are non-collinear

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To find the relationship between the points P, Q, and R, we will follow these steps: ### Step 1: Define the Points We have three points defined as follows: - \( P = (-\sin(\beta - \alpha), -\cos(\beta)) \) - \( Q = (\cos(\beta - \alpha), \sin(\beta)) \) - \( R = (\cos(\beta - \alpha + \theta), \sin(\beta - \theta)) \) ...
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