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The line (x)/(a)+(y)/(b)=1 moves in such...

The line `(x)/(a)+(y)/(b)=1` moves in such a way that `(1)/(a^2)+(1)/(b^2)=(1)/(c^2)`, where c is a constant. The locus of the foot of the perpendicular from the origin on the given line is `x^2+y^2=c^2`.

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