The lines `2x+3y+19=0` and `9x+6y-17=0` , cut the coordinate axes at concyclic points.

The lines 2x+3y+19=0 and 9x+6y-17=0 cuts the coordinate axes in

The algebraic sum of distances of the line ax + by + 2 = 0 from (1,2), (2,1) and (3,5) is zero and the lines bx - ay + 4 = 0 and 3x + 4y + 5=0 cut the coordinate axes at concyclic points. Then (a) a+b=-2/7 (b) area of triangle formed by the line ax+by+2=0 with coordinate axes is 14/5 (c) line ax+by+3=0 always passes through the point (-1,1) (d) max {a,b}=5/7

Show that the lines 3x-y+3=0 and x-3y-6=0 cut the coordinate axes at concylic points. Show that the equation of the circle passing through these points is x^(2)+y^(2)-5x-y-6=0

If lines 2x-3y+6=0 and kx+2y=12=0 cut the coordinate axes in concyclic points, then the value of |k| is

The lines 2x-5y+1=0 and 10x-4y-3=0 meets the coordinate axes in concylic points, then equation to the circle is

If the lines a_1x+b_1y+c_1=0 and a_2x+b_2y+c_2=0 cut the coordinae axes at concyclic points, then prove that |a_1a_2|=|b_1b_2|

If the lines 2x-3y+7=0, 3x+ky+5=0 cut the coordinate axes in concyclic points then k=

If the lines x-2y+3=0, 3x+ky+7=0 cut the coordinate axes in concylic points, then k=

If the 4 points made by intersection of lines 2x-y+1=0, x-2y+3=0 with the coordinate axes are concylic then centre of circle is

If the lines 2x+3y+1=0, 6x+4y+1=0 intersect the co-ordinate axes in 4 points, then the circle passing through the points is