The equations of the perpendicular bisectors of the sides `A Ba n dA C` of triangle `A B C` are `x-y+5=0` and `x+2y=0` , respectively. If the point `A` is `(1,-2)` , then find the equation of the line `B Cdot`

The sides A Ba n dA C of a triangle A B C are respectively 2x+3y=29a n dx+2y=16 respectively. If the mid-point of B Ci s(5,6) then find the equation of B Cdot

The equation of perpendicular bisectors of side AB,BC of triangle ABC are x-y=5 , x+2y=0 respectively and A(1,-2) then coordinate of C

The equation of perpendicular bisectors of the side AB and AC of a triangle ABC are x-y+5=0 and x+2y=0 respectively vertex A is (1,-2) Area of triangle A B C is (in sq. units) (A) (36)/5 (B) (18)/5 (C) (72)/5 (D) None of these

The equation of perpendicular bisectors of the side AB and AC of a triangle ABC are x-y+5=0 and x+2y=0 respectively vertex A is (1,-2) Area of Delta A B C is (a) (36)/5 (b) (18)/5 (c) (72)/5 (d) None of these

Let the equations of perpendicular bisectors of sides AC and of Delta ABCbe x+y=3 and x-y=1 respectively Then vertex A is is (0,0) The orthocentre of DeltaABC is

Let the equations of perpendicular bisectors of sides AC and AB of Delta ABC is x + y=3 and x - y=1 respectively Then vertex A is is (0,0) The circumcentre of the DeltaABC is

In triangle A B C , the equation of the right bisectors of the sides A B and A C are x+y=0 and y-x=0 , respectively. If A-=(5,7) , then find the equation of side B Cdot

Three sides A B ,A Ca n dC A of triangle A B C are 5x-3y+2=0,x-3y-2=0a n dx+y-6=0 respectively. Find the equation of the altitude through the vertex Adot

Orthocenter and circumcenter of a "triangle"A B C are (a , b)a n d(c , d) , respectively. If the coordinates of the vertex A are (x_1,y_1), then find the coordinates of the middle point of B Cdot

In a triangle, ABC, the equation of the perpendicular bisector of AC is 3x - 2y + 8 = 0 . If the coordinates of the points A and B are (1, -1) & (3, 1) respectively, then the equation of the line BC & the centre of the circum-circle of the triangle ABC will be