In a triangle `A B C` , the bisectors of angles `Ba n dC` lies along the lines `x=ya n dy=0.` If `A` is `(1,2)` , then the equation of line `B C` is (a) `2x+y=1` (b) `3x-y=5` (c) `x-2y=3` (d) `x+3y=1`

Equation of the bisector of angle B of the triangle ABC is y = x . If A is (2,6) and B is (1, 1) ; equation of side BC is (A) 2x + y - 3 = 0 (B) x-5y+ 4 =0 (C) x- 6y + 5 = 0 (D) none of these

Given ABCD is a parallelogram with vertices as A(1,2),B(3,4) and C(2,3) . Then the equation of line AD is (A) x+y+1=0 (B) x-y+1=0 (C) -x+y+1=0 (D) x+y-1=0

A B C is a variable triangle such that A is (1, 2), and Ba n dC on the line y=x+lambda(lambda is a variable). Then the locus of the orthocentre of "triangle"A B C is x+y=0 (b) x-y=0 x^2+y^2=4 (d) x+y=3

In a triangle A B C , if A is (2,-1),a n d7x-10 y+1=0 and 3x-2y+5=0 are the equations of an altitude and an angle bisector, respectively, drawn from B , then the equation of B C is (a) a+y+1=0 (b) 5x+y+17=0 (c) 4x+9y+30=0 (d) x-5y-7=0

A B C is a variable triangle such that A is (1,2) and B and C lie on line y=x+lambda (where lambda is a variable). Then the locus of the orthocentre of triangle A B C is (a) (x-1)^2+y^2=4 (b) x+y=3 (c) 2x-y=0 (d) none of these

Two straight lines u=0a n dv=0 pass through the origin and the angle between them is tan^(-1)(7/9) . If the ratio of the slope of v=0 and u=0 is 9/2 , then their equations are (a) y+3x=0 and 3y+2x=0 (b) 2y+3x=0 and 3y+x=0 (c) 2y=3x and 3y=x (d) y=3x and 3y=2x

The equations of the perpendicular bisectors of the sides A Ba n dA C of triangle A B C are x-y+5=0 and x+2y=0 , respectively. If the point A is (1,-2) , then find the equation of the line B Cdot

The equations of the perpendicular bisectors of the sides A Ba n dA C of triangle A B C are x-y+5=0 and x+2y=0 , respectively. If the point A is (1,-2) , then find the equation of the line B Cdot

ABC is a variable triangle such that A is (1, 2), and B and C on the line y=x+lambda(lambda is a variable). Then the locus of the orthocentre of DeltaA B C is (a) x+y=0 (b) x-y=0 x^2+y^2=4 (d) x+y=3

One of the bisector of the angle between the lines a(x-1)^2 + 2h(x-1)(y-2) + b (y-2)^2 = 0 is x + 2y - 5 = 0 . Then other bisector is (A) 2x-y=0 (B) 2x+y=0 (C) 2x+y-4=0 (D) x-2y+3=0