If the extremities of the base of an isosceles triangle are the points (2a,0) and (0,a), and the equation of one of the sides x=2a, then the area of the triangle is

If the extremities of the base of an isosceles triangle are the points (2a ,0) and (0, a), and the equation of one of the side is x=2a , then the area of the triangle is 5a^2s qdotu n i t s (b) (5a^2)/2s qdotu n i t s (25 a^2)/2s qdotu n i t s (d) none of these

If the ends of the base of an isosceles triangle are at (2, 0) and (0, 1), and the equation of one side is x = 2 , then the orthocenter of the triangle is

The extremities of the base of an isosceles triangle are (2,0)a n d(0,2) . If the equation of one of the equal side is x=2, then the equation of other equal side is (a) x+y=2 (b) x-y+2=0 (c) y=2 (d) 2x+y=2

The ends of the base of an isosceles triangle are at (2a, 0)and (0, a). The equation of one side is x = 2a. The equation of the other side, is

In an isoceles triangle OAB , O is the origin and OA=OB=6 . The equation of the side AB is x-y+1=0 Then the area of the triangle is

The area of an isosceles triangle having base 2 cm and the length of one of the equal sides 4 cm is

The perimeter of an isosceles triangle is 49 m and the length of one of its equal sides is 17m. Find the length of the base of the triangle.

If A(3,4) and B(-5,-2) are the extremities of the base of an isosceles triangle ABC with tan C = 2 , then point C can be

Find the area of an isosceles triangle with perimeter 36 cm and base 16 cm.

The ends of the base of an isosceles triangle are (2sqrt(2), 0) and (0, sqrt(2)) . One side is of length 2sqrt(2) . If Delta be the area of triangle, then the value of [Delta] is (where [.] denotes the greatest integer function)