One ticket is selected at random from 100 tickets numbered 00,01,02,...,98,99. If `X, a n dY` denotes the sum and product of the digits on the tickets, then 57`P(X=9//Y=0)` is equal to `2//19` b. `19//100` c. `1//50` d. none of these

One ticket is selected at random from 100 tickets numbered 00,01,02,...,98,99. If x_1, a n dx_2 denotes the sum and product of the digits on the tickets, then P(x_1=9//x_2=0) is equal to 2//19 b. 19//100 c. 1//50 d. none of these

One ticket is selected at random from 100 tickets numbered 00,01,02, …, 99. Suppose A and B are the sum and product of the digit found on the ticket, respectively. Then P((A=7)//(B=0)) is given by

One ticket is selected at random from 100 tickets numbered 00, 01, 02, 03,…………..99. Suppose x is the sum of the digits and y is the product of the digits, then the probability that x = 9 and y = 0 is

One ticket is selected at ransom form 50 tickets numbered 00,01,02,…,49. Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, is

One ticket is selected at random from 50 tickets numbered 00, 01, 02, ... , 49. Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, equals (1) 1/14 (2) 1/7 (3) 5/14 (4) 1/50

One ticket is selected at random from 50 tickets numbered 00, 01, 02, ... , 49. Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, equals (1) 1/14 (2) 1/7 (3) 5/14 (4) 1/50

One ticket is selected at random from 50 tickets numbered 00, 01, 02, ... , 49. Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, equals (1) 1/14 (2) 1/7 (3) 5/14 (4) 1/50

For the equation, 3x^2+p x+3=0,p >0, if one of the roots is square of the other, then ' p ' is equal to: 1/3 (b) 3 (c) 1 (d) None of these

A natural number is chosen at random from the first 100 natural numbers. The probability that x+(100)/x > 50 is 1//10 b. 11//50 c. 11//20 d. none of these

A natural number is chosen at random from the first 100 natural numbers. The probability that x+(100)/x > 50 is 1//10 b. 11//50 c. 11//20 d. none of these