`Ea n dF` are two independent events. The probability that both `Ea n dF` happen is 1/12 and the probability that neither `Ea n dF` happens is 1/2. Then, `A) P(E)=1//3, P(F)=1//4` `B) P(E)=1//4, P(F)=1//3` `C) P(E)=1//6, P(F)=1//2` `D) P(E)=1//2, P(F)=1//6`

E and F are two independent events. The probability that both e and F happen is 1/12 and the probability that neither E nor F happens is 1/2. Then

Let E and F be two independent events. The probability that exactly one of them occurs is 11/25 and the probability if none of them occurring is 2/25 . If P(T) denotes the probability of occurrence of the event T , then (a) P(E)=4/5,P(F)=3/5 (b) P(E)=1/5,P(F)=2/5 (c) P(E)=2/5,P(F)=1/5 (d) P(E)=3/5,P(F)=4/5

If E and F are independent events such that 0 lt P(E) lt 1 and 0 lt P(F) lt 1 , then

If P(A) = 1/2 and P(AcapB)=1/3 , then the probability that A happens but B does not happen is

If A\ a n d\ B are two independent events such that P(barAnnB)=2/15\ a n d\ P( A nn barB )=1/6 , then write the values of P(A)a n d\ P(B)

If E and F are two independent events and P(E)=1/3,P(F)=1/4, then find P(EuuF) .

If E and F are events such that P(E) = 1/4, P(F) =1/2 and P(E and F) = 1/8, find P(E or F)

If A and B are two independent events with P(A) =1/3 and P(B) = 1/4 , then P(B/A) is equal to

Let E and F be the events such that, P(E )=(1)/(3), P(F) = (1)/(4) and P(E cap F)=(1)/(5) , find P((barF)/(barE)) .

The Probability that at least one of the events E_(1) and E_(2) will occur is 0.6. If the probability of their occurrence simultaneously is 0.2, then find P(barE_(1))+P(barE_(2))