Statement 1: Our of 5 tickets consecutively numbered, three are drawn at random. The chance that the numbers on them are in A.P. is `2//15`.
Statement 2: Out of `2n+1` tickets consecutively numbered, three are drawn at random, the chance that the numbers on them are in A.P. is `3n//(4n^2-1)`.

Out of (2n+1) tickets consecutively numbered, three are drawn at random. Find the chance that the numbers on them are in AP.

Statement-1: Out of 21 tickets with number 1 to 21, 3 tickets are drawn at random, the chance that the numbers on them are in AP is (10)/(133) . Statement-2: Out of (2n+1) tickets consecutively numbered three are drawn at ranodm, the chance that the number on them are in AP is (4n-10)/ (4n^(2)-1) .

Out of 7 tickets consecutively numbered 3 are drawn at random. The probability for the numbers on the tickets to be in A.P. is

There are 12 tickets numbered 1 to 12. A ticket is drawn at random. Find the probability that the number on this ticket is either a multiple of 3 or 4.

A bag contains tickets numbered 1 to 20 . Two tickets are drawn at random , Find the probability that sum of the two numbers on the tickets is even .

There are 25 tickets numbered from 1 to 25. A ticket is drawn at random. Find the probability that the number of that ticket is either a multiple of 2 or multiple of 3.

A box contains 25 tickets numbered 1 to 25 Two tickets are drawn at random . What is the probability that the product of the numbers is even ?

From a set of 17 cards numbered 1,2,3,4,…, 16,17 , one card is drawn at random : Show that the chance that its number is divisible by 3 or 7 is (7)/(17) .

The sum of three consecutive numbers in A.P. is 51 and the product of their extremes is 273. Find the numbers.

If the sum of three consecutive numbers in A.P., is 24 and their product is 440, find the numbers.