Of the three independent events `E_(1),E_(2),and E_(3),` the probability that only `E_(1)` occurs is `alpha` only `E_(2)` occurs is `beta,` and only `E_(3)` occurs is `gamma.` Let the probability p that none of events `E_(1),E_(2), or E_(3)` occurs satisfy the equations `(alpha-2beta)p=alpha betaand (beta-3gamma)p=betagamma.` All the given probabilities are assumed to lie in the interval `(0,1).` Then
`("Probability of occurrence of"E_(1))/("Probability of occurence of"E_(3))=______.`

Of the three independent event E_(1),E_(2) and E_(3) , the probability that only E_(1) occurs is alpha , only E_(2) occurs is beta and only E_(3) occurs is gamma . If the probavvility p that none of events E_(1), E_(2) or E_(3) occurs satisfy the equations (alpha - 2beta)p = alpha beta and (beta - 3 gamma) p = 2 beta gamma . All the given probabilities are assumed to lie in the interval (0, 1). Then, ("probability of occurrence of " E_(1))/("probability of occurrence of " E_(3)) is equal to

Of the three independent event E_(1),E_(2) and E_(3) , the probability that only E_(1) occurs is alpha , only E_(2) occurs is beta and only E_(3) occurs is gamma . If the probavvility p that none of events E_(1), E_(2) or E_(3) occurs satisfy the equations (alpha - 2beta)p = alpha beta and (beta - 3 gamma) p = 2 beta gamma . All the given probabilities are assumed to lie in the interval (0, 1). Then, ("probability of occurrence of " E_(1))/("probability of occurrence of " E_(3)) is equal to

If P(E) = 0.25 , What is the probability of not E .

If P(E)=0.08 , What is the probability of not E .

If P(E)=0. 05 , what is the probability of not E?

The Probability that at least one of the events E_(1) and E_(2) will occur is 0.6. If the probability of their occurrence simultaneously is 0.2, then find P(barE_(1))+P(barE_(2))

The probability that atleast one of the two events A and B occurs is 0.6. If A and B occur simultaneously with probability 0.3, evaluate P(barA)+P(barB) .

The probability of event A is 3//4 . The probability of event B , given that event A occurs is 1//4 . The probability of event A , given that event B occurs is 2//3 . The probability that neither event occurs is

If E and F are two independent events and P(E)=1/3,P(F)=1/4, then find P(EuuF) .

A and B are two independent events.The probability that both A and B occur is 1/6 and the probability that neither of them occurs is 1/3.Then the probability of the two events are respectively: