Find the point of intersection of the ci...

Find the point of intersection of the circle `x^2+y^2-3x-4y+2=0` with the x-axis.

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The equation of the circle having its centre on the line x+2y-3=0 and passing through the points of intersection of the circles x^2+y^2-2x-4y+1=0a n dx^2+y^2-4x-2y+4=0 is

Find the equation of the circle passing through the points of intersection of the circles x^2 + y^2 - 2x - 4y - 4 = 0 and x^2 + y^2 - 10x - 12y +40 = 0 and whose radius is 4.

The equation of the circle having its centre on the line x+2y-3=0 and passing through the points of intersection of the circles x^2+y^2-2x-4y+1=0a n dx^2+y^2-4x-2y+4=0 is x^2+y^2-6x+7=0 x^2+y^2-3y+4=0 c. x^2+y^2-2x-2y+1=0 x^2+y^2+2x-4y+4=0

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The equation of the circle passing through the point of intersection of the circles x^2+y^2-4x-2y=8 and x^2+y^2-2x-4y=8 and the point (-1,4) is (a) x^2+y^2+4x+4y-8=0 (b) x^2+y^2-3x+4y+8=0 (c) x^2+y^2+x+y=0 (d) x^2+y^2-3x-3y-8=0

The equation of the circle passing through the point of intersection of the circles x^2+y^2-4x-2y=8 and x^2+y^2-2x-4y=8 and the point (-1,4) is x^2+y^2+4x+4y-8=0 x^2+y^2-3x+4y+8=0 x^2+y^2+x+y=0 x^2+y^2-3x-3y-8=0

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