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Consider the family of circles x^2+y^2-2...

Consider the family of circles `x^2+y^2-2x-2lambday-8=0` passing through two fixed points `Aa n dB` . Then the distance between the points `Aa n dB` is_____

A

4

B

`4 sqrt(2)`

C

6

D

8

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To find the distance between the points A and B that lie on the family of circles given by the equation \( x^2 + y^2 - 2x - 2\lambda y - 8 = 0 \), we can follow these steps: ### Step-by-Step Solution: 1. **Rearranging the Circle Equation**: The equation of the family of circles is given as: \[ x^2 + y^2 - 2x - 2\lambda y - 8 = 0 ...
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