A circle `x^2 +y^2 + 4x-2sqrt2 y + c = 0` is the director circle of circle `S_1 and S_1` is the director circle of circle `S_2`, and so on. If the sum of radii of all these circles is 2, then find the value of c.

A circle x^2+y^2+4x-2sqrt(2)y+c=0 is the director circle of the circle S_1a n dS_1 is the director circle of circle S_2, and so on. If the sum of radii of all these circles is 2, then the value of c is ksqrt(2) , where the value of k is___________

A circle S of radius ' a ' is the director circle of another circle S_1,S_1 is the director circle of circle S_2 and so on. If the sum of the radii of all these circle is 2, then the value of ' a ' is (a) 2+sqrt(2) (b) 2-1/(sqrt(2)) (c) 2-sqrt(2) (d) 2+1/(sqrt(2))

Statement-1: The centre of the circle passing through the points (0, 0), (1, 0) and touching the circle C : x^(2)+y^(2)=9 lies inside the circle. Statement-2: If a circle C_(1) passes through the centre of the circle C_(2) and also touches the circle, the radius of the circle C_(2) is twice the radius of circle C_(1)

If the circle x^2+y^2=1 is completely contained in the circle x^2+y^2+4x+3y+k=0 , then find the values of kdot

If the circle x^2+y^2 +4x+22y + c = 0 bisects the circumference of the circle x^2 + y^2-2x + 8y-d = 0 ,then (c+d) is equal to

The line 2x-y+1=0 is tangent to the circle at the point (2, 5) and the center of the circle lies on x-2y=4 . Then find the radius of the circle.

the equation to the director circle of (x^2)/6+(y^2)/4=1 is

The line 2x - y + 1 = 0 is tangent to the circle at the point (2,5) and the centre of the circles lies on x-2y = 4. The radius of the circle is :

If one of the diameters of the circle x^2+y^2-2x-6y+ 6 = 0 is a chord to the circle with centre (2, 1), then the radius of circle is:

Prove that the circle x^2 + y^2 =a^2 and (x-2a)^2 + y^2 = a^2 are equal and touch each other. Also find the equation of a circle (or circles) of equal radius touching both the circles.