Through a fixed point (h, k) secants are...

Through a fixed point (h, k) secants are drawn to the circle `x^2 +y^2 = r^2`. Then the locus of the mid-points of the secants by the circle is

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Through a fixed point (h,k), secant are drawn to the circle x^(2)+y^(2)=r^(2) . Show that the locus of the midpoints of the secants by the circle is x^(2)+y^(2)=hx+ky .

Through a fixed point (h,k) secants are drawn to the circle x^(2)+y^(2)=r^(2) . Show that the locus of the mid points of the position of the secants intercepted by the circle is x^(2)+y^(2)=hx+ky .

From the origin, chords are drawn to the circle (x-1)^2 + y^2 = 1 . The equation of the locus of the mid-points of these chords

If from the origin a chord is drawn to the circle x^(2)+y^(2)-2x=0 , then the locus of the mid point of the chord has equation

Tangents PA and PB are drawn to the circle x^2+y^2=4 ,then locus of the point P if PAB is an equilateral triangle ,is equal to

From points on the straight line 3x-4y + 12 = 0, tangents are drawn to the circle x^2 +y^2 = 4 . Then, the chords of contact pass through a fixed point. The slope of the chord of the circle having this fixed point as its mid-point is

From the point P(2, 3) tangents PA,PB are drawn to the circle x^2+y^2-6x+8y-1=0 . The equation to the line joining the mid points of PA and PB is

Let A B be chord of contact of the point (5,-5) w.r.t the circle x^2+y^2=5 . Then find the locus of the orthocentre of the triangle P A B , where P is any point moving on the circle.

If a circle passes through the point (a,b) and cuts the circle x^2+y^2=k^2 orthogonally then the locus of its centre is

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