If the circles `x^2+y^2+2x+2ky+6=0` and `x^2+y^2+2ky+k=0` intersect orthogonally then k equals (A) `2 or -3/2` (B) `-2 or -3/2` (C) `2 or 3/2` (D) `-2 or 3/2`

If the curves 2x^(2)+3y^(2)=6 and ax^(2)+4y^(2)=4 intersect orthogonally, then a =

If the two circles 2x^2+2y^2-3x+6y+k=0 and x^2+y^2-4x+10 y+16=0 cut orthogonally, then find the value of k .

If the two circles 2x^2+2y^2-3x+6y+k=0 and x^2+y^2-4x+10 y+16=0 cut orthogonally, then find the value of k .

The circles x^2+y^2-6x-8y+12=0, x^2+y^2-4x+6y+k=0 , cut orthogonally then k=

Find k if the circles x^2+y^2-5x-14y-34=0 and x^2+y^2+2x+4y+k=0 are orthogonal to each other.

Show that x^3-3x y^2=(-2) and 3x^2\ y-y^3=2 intersect orthogonally.

For the circles 3x^2+3y^2+x+2y-1=0 , 2x^2+2y^2+2x-y-1=0 radical axis is

The two circles x^(2)+y^(2)-2x-3=0 and x^(2)+y^(2)-4x-6y-8=0 are such that

If the circles x^2+y^2-2x-2y-7=0 and x^2+y^2+4x+2y+k=0 cut orthogonally, then the length of the common chord of the circles is a.(12)/(sqrt(13)) b. 2 c. 5 d. 8

The equation of the circle passing through the point of intersection of the circles x^2 + y^2 - 6x + 2y + 4 = 0 and x^2 + y^2 + 2x - 6y - 6=0 and having its centre on y=0 is : (A) 2x^2 + 2y^2 + 8x + 3 = 0 (B) 2x^2 + 2y^2 - 8x - 3 = 0 (C) 2x^2 + 2y^2 - 8x + 3 = 0 (D) none of these