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An isosceles triangle A B C is inscribed...

An isosceles triangle `A B C` is inscribed in a circle `x^2+y^2=a^2` with the vertex `A` at `(a ,0)` and the base angle `B` and `C` each equal `75^0` . Then the coordinates of an endpoint of the base are (a) `(-(sqrt3a)/2, a/2)` (b) `(-(sqrt3a)/2, a)` (c)`(a/2,(sqrt3a)/2)` (d) `((sqrt3a)/2,-a/2)`

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