If the lines `3x-4y+4=0` and `6x-8y-7=0` are tangents to a circle, then find the radius of the circle.

If the lines 3 x - 4y + 4 = 0 and 6x - 8y - 7 = 0 are tangents to a circle , then the radius of the circle is

If 2x-4y=9 and 6x-12y+7=0 are parallel tangents to circle, then radius of the circle, is

Centre of a circle of radius 4sqrt(5) lies on the line y=x and satisfies the inequality 3x+6y > 10. If the line x+2y=3 is a tangent to the circle, then the equation of the circle is

The line 2x-y+1=0 is tangent to the circle at the point (2, 5) and the center of the circle lies on x-2y=4 . Then find the radius of the circle.

The line 2x - y + 1 = 0 is tangent to the circle at the point (2,5) and the centre of the circles lies on x-2y = 4. The radius of the circle is :

If the line x+3y=0 is tangent at (0,0) to the circle of radius 1, then the centre of one such circle is

Straight line 3x-4y=4/(pi)sin^(-1)(a^(8)+1)+2cos^(-1)(a^(12)+1)-sec^(-1)(a^(2)+1),aepsilonR & 6x-8y=7 are tangents to a circle then the length of arc of this circle which makes on angle of 40/3 at its centre is

In the xy-plane , a circle with center (6,0) is tangent to the line y=x. what is the radius of the circle ?

If the line 4x - 3y = -12 is tangent at point (-3,0) and the line 3x+4y=16 is tangent at the point (4,1) to a circle then equation of circle

Tangents drawn from P(1, 8) to the circle x^2 +y^2 - 6x-4y - 11=0 touches the circle at the points A and B, respectively. The radius of the circle which passes through the points of intersection of circles x^2+y^2 -2x -6y + 6 = 0 and x^2 +y^2 -2x-6y+6=0 the circumcircle of the and interse DeltaPAB orthogonally is equal to