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Find the values of alpha so that the poi...

Find the values of `alpha` so that the point `P(alpha^2,alpha)` lies inside or on the triangle formed by the lines `x-5y+6=0,x-3y+2=0a n dx-2y-3=0.`

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Find the values of alpha so that the point P(alpha^2,alpha) lies inside or on the triangle formed by the lines x-5y+6=0,x-3y+2=0 a n d x-2y-3=0.

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Find the area of the triangle formed by the lines y+x-6=0, 3y-x+2=0 and 3y=5x+2 .

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The complete set of real values of 'a' such that the point lies triangle p(a, sin a) lies inside the triangle formed by the lines x-2y +2= 0; x+y=0 and x-y-pi=0

Find the area of triangle formed by the lines : y=0,\ x=2\ a n d\ x+2y=3.

Statement 1: The value of alpha for which the point (alpha,alpha^2) lies inside the triangle formed by the lines x=0,x+y=2 and 3y=x is (0,1)dot Statement 2: The parabola y=x^2 meets the line x+y=2 at (1,1)dot

If point P(alpha, alpha^2-2) lies inside the triangle formed by the lines x + y=1 , y=x + 1 and y=-1 then alpha in

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