The vertex of a parabola is (2, 2) and the coordinats of its two extremities of latus rectum are `(-2,0)` and (6, 0). Then find the equation of the parabola.

If the vertex of a parabola is (0, 2) and the extremities of latusrectum are (-6, 4) and (6, 4) then, its equation, is

Find the equation of the parabola the extremities of whose latus rectum are (1, 2) and (1, -4).

Find the equation of the parabola the extremities of whose latus rectum are (1, 2) and (1, -4).

The equations of the parabolas the extremities of whose latus rectum are (3, 5) and (3,-3)

Find the equation of a parabola having its focus at S(2,0) and one extremity of its latus rectum at (2, 2)

For the following parabola, find the coordinates if the focus, length of the latus rectum, equation of the axis and the equation of the directrix. y^2=18x

If the points (0,4)a n d(0,2) are respectively the vertex and focus of a parabola, then find the equation of the parabola.

If the points (0,4)a n d(0,2) are respectively the vertex and focus of a parabola, then find the equation of the parabola.

If the point (2, 3) is the focus and x = 2y + 6 is the directrix of a parabola, find (i) The equation of the axis. (ii) The co-ordinates of the vertex. (iii) Length of the latus rectum. (iv) Equation of the latus rectum.

Find the value of lambda if the equation (x-1)^2+(y-2)^2=lambda(x+y+3)^2 represents a parabola. Also, find its focus, the equation of its directrix, the equation of its axis, the coordinates of its vertex, the equation of its latus rectum, the length of the latus rectum, and the extremities of the latus rectum.