The angle between the tangents to the curve `y=x^2-5x+6` at the point (2, 0) and (3, 0) is (a)`pi/2` (b) `pi/3` (c) `pi` (d) `pi/4`

Options

A. `(pi)/(2)`
B. `(pi)/(3)`
C. `(pi)/(6)`
D. `(pi)/(4)`

Explanation

To find the angle between the tangents to the curve \( y = x^2 - 5x + 6 \) at the points \( (2, 0) \) and \( (3, 0) \), we can follow these steps:

### Step-by-step Solution:

1. **Find the Derivative of the Curve:**
The given curve is \( y = x^2 - 5x + 6 \). To find the slope of the tangent at any point on the curve, we need to differentiate it with respect to \( x \).
\[
\frac{dy}{dx} = 2x - 5
...