If O is the origin, OP = 3, with direction ratios -1, 2 and -2, then find the coordinates of P.

If O is the origin, O P=3 with direction ratios -1,2,a n d-2, then find the coordinates of Pdot

O is the origin and P is point at a distance of 3 units from origin. If direction ratios of OP are lt 1,-2,-2 gt , then the coordinates of P are

O is origin and P is a point at a distance of 7 units from origin if the direction ratios of OP are lt 3 ,-2, 6 gt , then the coordinates of P are (i) (3,-2,6) (ii) (21,-14,42) (iii) (3/7,-2/7,6/7) (iv) none of these

If O be the origin and OP=r and OP makes an angle theta with the positive direction of x-axis and lies in the XY plane find the coordinates of P.

Find the vector equation of a plane which is at a distance of 6 units from the origin and has 2, -1, 2 as the direction ratios of a normal to it. Also, find the coordinates of the foot of the normal drawn from the origin.

Find the angles at which a line with direction ratios 2,-1,2 is inclined to each of the coordinate axes.

If the origin is shifted (1, 2, -3) without changing the directions of the axis, then find the new coordinates of the point (0, 4, 5) with respect to new frame.

The foot of the perpendicular drawn from the origin to a plane is (1,2,-3)dot Find the equation of the plane. or If O is the origin and the coordinates of P is (1,2,-3), then find the equation of the plane passing through P and perpendicular to O Pdot

The origin O,B (-6,9) and C (12, -3) are vertices of triangle OBC, Point P divides OB in the ratio 1 : 2 and point Q divides OC in the ratio 1 : 2 Find the co-ordinates of points P and Q. Also show that PQ = (1)/(3) BC.

If O be the origin and the coordinates of P be (1," "2," "" "3) , then find the equation of the plane passing through P and perpendicular to OP.