Find the locus of a point, the sum of squares of whose distance from the planes `x-z=0,x-2y+z=0` and `x+y+z=0` is 36

Explanation

To find the locus of a point whose sum of squares of distances from the planes \(x - z = 0\), \(x - 2y + z = 0\), and \(x + y + z = 0\) is 36, we will follow these steps:

### Step 1: Identify the point and the planes
Let the point be \(P(\alpha, \beta, \gamma)\). The given planes are:
1. Plane 1: \(x - z = 0\)
2. Plane 2: \(x - 2y + z = 0\)
3. Plane 3: \(x + y + z = 0\)

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