Find the equation of the plane which passes through the point `(1,2,3)` and which is at the minimum distance from the point `(-1,0,2)dot`

Explanation

To find the equation of the plane that passes through the point \( (1, 2, 3) \) and is at the minimum distance from the point \( (-1, 0, 2) \), we can follow these steps:

### Step 1: Identify the Points
Let point \( A \) be \( (1, 2, 3) \) (the point through which the plane passes) and point \( B \) be \( (-1, 0, 2) \) (the point from which we want to minimize the distance to the plane).

### Step 2: Find the Direction Vector
We need to find the vector \( \overrightarrow{AB} \) which is the vector from point \( A \) to point \( B \). This can be calculated as:
\[
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