Two perpendicular tangents drawn to the ellipse `(x^2)/(25)+(y^2)/(16)=1` intersect on the curve.

On which curve does the perpendicular tangents drawn to the hyperbola (x^2)/(25)-(y^2)/(16)=1 intersect?

On which curve does the perpendicular tangents drawn to the hyperbola (x^(2))/(25)-(y^(2))/(16)=1 intersect?

Number of points on the ellipse (x^(2))/(25) + (y^(2))/(16) =1 from which pair of perpendicular tangents are drawn to the ellipse (x^(2))/(16) + (y^(2))/(9) =1 is

The number of points on the ellipse (x^2)/(50)+(y^2)/(20)=1 from which a pair of perpendicular tangents is drawn to the ellipse (x^2)/(16)+(y^2)/9=1 is 0 (b) 2 (c) 1 (d) 4

Number of perpendicular tangents that can be drawn on the ellipse (x^(2))/(16)+(y^(2))/(25)=1 from point (6, 7) is

Statement-1: Tangents drawn from any point on the circle x^(2)+y^(2)=25 to the ellipse (x^(2))/(16)+(y^(2))/(9)=1 are at right angle Statement-2: The locus of the point of intersection of perpendicular tangents to an ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 is its director circle x^(2)+y^(2)=a^(2)+b^(2) .

IF the locus of the point of intersection of two perpendicular tangents to a hyperbola (x^(2))/(25) - (y^(2))/(16) =1 is a circle with centre (0, 0), then the radius of a circle is

If two tangents drawn to the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 intersect perpendicularly at P. then the locus of P is a circle x^(2)+y^(2)=a^(2)+b^(2) the circle is called

The points on the ellipse (x^(2))/(2)+(y^(2))/(10)=1 from which perpendicular tangents can be drawn to the hyperbola (x^(2))/(5)-(y^(2))/(1) =1 is/are

If F_1 and F_2 are the feet of the perpendiculars from the foci S_1a n dS_2 of the ellipse (x^2)/(25)+(y^2)/(16)=1 on the tangent at any point P on the ellipse, then prove that S_1F_1+S_2F_2geq8.