A common tangent to `9x^2-16y^2 = 144` and `x^2 + y^2 = 9`, is

Explanation

To find a common tangent to the hyperbola given by the equation \(9x^2 - 16y^2 = 144\) and the circle given by the equation \(x^2 + y^2 = 9\), we can follow these steps:

### Step 1: Rewrite the equations in standard form
1. **Hyperbola**: The equation \(9x^2 - 16y^2 = 144\) can be rewritten as:
\[ \frac{x^2}{16} - \frac{y^2}{9} = 1 \]
Here, \(a^2 = 16\) and \(b^2 = 9\).
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