Find the equation of tangents to the curve `4x^2-9y^2=1` which are parallel to `4y=5x+7.`

Explanation

To find the equation of the tangents to the curve \(4x^2 - 9y^2 = 1\) that are parallel to the line \(4y = 5x + 7\), we can follow these steps:

### Step 1: Find the slope of the given line
The equation of the line is given as \(4y = 5x + 7\). We can rearrange this into the slope-intercept form \(y = mx + c\).

\[ y = \frac{5}{4}x + \frac{7}{4} \]
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