The point of intersection of the lines `(x-5)/(3)=(y-7)/(-1)and(x+3)/(-36)=(y-3)/(2)=(z-6)/(4)` is

The point of intersection of the lines (x-5)/3=(y-7)/(-1)=(z+2)/1a n d=(x+3)/(-36)=(y-3)/2=(z-6)/4 is a. (21 ,5/3,(10)/3) b. (2,10 ,4) c. (-3,3,6) d. (5,7,-2)

Equation of the plane passing through the point of intersection of lines (x-1)/(3)=(y-2)/(1)=(z-3)/(2)&(x-3)/(1)=(y-1)/(2)=(z-2)/(3) and perpendicular to the line (x+5)/(2)=(y-3)/(3)=(z+1)/(1) is

The equation of the plane which passes through the point of intersection of lines ""(x-1)/3=(y-2)/1=(z-3)/2"","and"(x-3)/1=(y-1)/2=(z-2)/3 and at greatest distance from point (0,0,0) is a. 4x+3y+5z=25 b. 4x+3y=5z=50 c. 3x+4y+5z=49 d. x+7y-5z=2

Find the point of intersection of the lines 2x-3y+8=0 and 4x+5y=6

A line with cosines proportional to 2,7-5 drawn to intersect the lines (x-5)/3=(y-7)/-1=(z+2)/1 ; (x+3)/-3=(y-3)/2=(z-6)/4 .Find the co- ordinates of the points of intersection and the length intercepted on it.

Column I, Column II Image of the point (3,5,7) in the plane 2x+y+z=-18 is, p. (-1,1,-1) The point of intersection of the line (x-2)/(-3)=(y-1)/(-2)=(z-3)/2 and the plane 2x+y-z=3 is, q. (-21 ,-7,-5) The foot of the perpendicular from the point (1,1,2) to the plane 2x-2y+4z+5=0 is, r. (5/2,2/3,8/3) The intersection point of the lines (x-1)/2=(y-2)/3=(z-3)/4a n d(x-4)/5=(y-1)/2=z is, s. (-1/(12),(25)/(12),(-2)/(12))

Show that the following pairs of lines intersect. Also find their point of intersection : (i) (x-1)/(2) = (y-2)/(3)=(z-3)/(4) and (x-4)/(5)=(y-1)/(2)=z (ii) (x-4)/(1)=(y+3)/(-4) = (z+1)/(7) and (x-1)/(2) = (y+1)/(-3)=(z+10)/(8)

Find the point of intersection of the line, x/3 - y/4 = 0 and x/2 + y/3 = 1

Find the points on the lines (x-6)/3=(y-7)/(-1)=(z-4)/1 and x/(-3)=(y-9)/2=(z-2)/4 . Which are nearest to each other.

The distance of point of intersection of lines (x-4)/1=(x+3)/-4=(z-1)/7 and (x-1)/2=(y+1)/-3=(z+10)/8 from (1,-4,7) is