Find the equation of the plane containin...

Find the equation of the plane containing the lines 2x-y+z-3=0,3x+y+z=5 and a t a distance of `1/sqrt6` from the point (2,1,-1).

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Find the equation of the plane containing the lines 2x-y+z-3=0, 3x+y+z=5 and at a distance of 1/sqrt6 from the point (2,1,-1) .

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The equation of the plane containing the line 2x+z-4=0 nd 2y+z=0 and passing through the point (2,1,-1) is (A) x+y-z=4 (B) x-y-z=2 (C) x+y+z+2=0 (D) x+y+z=2

The equation of a plane passing through the line of intersection of the planes x+2y+3z = 2 and x - y + z = 3 and at a distance 2/sqrt 3 from the point (3, 1, -1) is

Let the equation of the plane containing line x-y-z-4=0=x+y+2z-4 and parallel to the line of intersection of the planes 2x+3y+z=1 and x+3y+2z=2 be x+Ay+Bz+C=0 . Then the values of |A+B+C-4| is …..

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