The position vectors of the four angular points of a tetrahedron OABC are `(0, 0, 0); (0, 0,2) , (0, 4,0)` and `(6, 0, 0)` respectively. A point P inside the tetrahedron is at the same distance `r` from the four plane faces of the tetrahedron. Find the value of `r`

The position vectors of the four angular points of a tetrahedron OABC are (0, 0, 0), (0, 0, 2), (0, 4, 0) and (6, 0, 0) , respectively. A point P inside the tetrahedron is at the same distance 'r' from the four plane faces of the tetrahedron. Then, the value of 9r is.....

The coordinates of the point equidistant from the points A(0, 0, 0), B(4, 0, 0), C(0, 6, 0) and D(0, 0, 8) is

The position vector of the vertices A, B & C of a tetrahedron ABCD are (1, 1, 1), (1, 0, 0) & (3, 0, 0) respectively. The altitude from the vertex D to the opposite face ABC meets the median through A of A B C at point E. If A D=4 units and value of tetrahedron =(2sqrt(2))/3, then the correct statement(s) among the following is/are: The altitude from vertex D=2 units There is only one possible position for point E There are two possible position for point E vector hat j- hat k is normal to the plane ABC

Find the coordinates of the point equidistant from the four points A(0,0,0) , B (a,0,0) , C(0,b,0) and D(0,0,c) .

If P(0, 1, 2), Q(4, -2, 1) and R(0, 0, 0) are three points, then anglePRQ is

The point equidistant from the point (0,0,0),(1,0,0,),(0,2,0) and (0,0,3) is

Find the coordinates of a point equidistant from the four points O(0,0,0), A(p,0,0), B(0,q,0) and C(0,0,r)

Find the coordinates of the point equidistant from the points (0,0,0),(2,0,0),(0,4,0) and (0,0,6)

The coordinates of the point which is equidistant from the points O(0,0,0) A (a,0,0), B(0,b,0) and C(0,0,c)

If P(5,1), Q(8,0), R(0,4), S(0,5) and 0(0,0) are plotted on the graph paper, then the point(s) on the X-axis is/are