The equation of the line `x+y+z-1=0`, `4x+y-2z+2=0` written in the symmetrical form is

Options

A. `(x+1)/(1)=(y-2)/(-2)= (z-0)/(1)`
B. `(x)/(1)= (y)/(-2)= (z-1)/(1)`
C. `(x+1//2)/(1)= (y-1)/(-2)= (z-1//2)/(1)`
D. `(x-1)/(2)= (y+2)/(-1)= (z-2)/(2)`

Explanation

To find the symmetrical form of the line represented by the equations of the planes \(x + y + z - 1 = 0\) and \(4x + y - 2z + 2 = 0\), we can follow these steps:

### Step 1: Understand the equations of the planes
The given equations represent two planes in three-dimensional space. The intersection of these two planes will give us a line.

### Step 2: Assume a parameter
To express the line in a symmetrical form, we can assume one of the variables as a parameter. Let's assume \(z = \lambda\).

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