Home
Class 12
MATHS
Find the probability that a leap year wi...

Find the probability that a leap year will have 53 Friday or 53 Saturdays.

Text Solution

Verified by Experts

The correct Answer is:
`(3)/(7)`

There are 366 days in a leap year. Also, there are 52 weeks and 2 days.
The prossible combinations of two days are as follows:
Sunday-Monday,
Monday-Tuesday,
Tuesday-Wednesday,
Wednesday-Thursday,
Thurday-Friday,
Friday-Saturday,
Saturday-Sunday
Now, let E be the event in which leap year will have 53 Fridays or 53 Saturdays.
We observe that there are three possibilities for event E, viz. Thursday-Friday, Friday-Saturday, and Saturday-Sunday. Since each pair of 2 equally likely,
`P(E) = (1)/(7) + (1)/(7) + (1)/(7) = (3)/(7)`
Promotional Banner

Topper's Solved these Questions

  • PROBABILITY I

    CENGAGE ENGLISH|Exercise Exercise 9.2|19 Videos
  • PROBABILITY I

    CENGAGE ENGLISH|Exercise Exercise 9.3|7 Videos
  • PROBABILITY I

    CENGAGE ENGLISH|Exercise Solved Example|9 Videos
  • PROBABILITY

    CENGAGE ENGLISH|Exercise Comprehension|2 Videos
  • PROBABILITY II

    CENGAGE ENGLISH|Exercise MULTIPLE CORRECT ANSWER TYPE|6 Videos

Similar Questions

Explore conceptually related problems

Find the probability that a leap year will have 53 Fridays or 53 Saturdays.

The probability that a leap year will have 53 Fridays or 3 Saturday is a. 2/7 b. 3/7 c. 4/7 d. 1/7

What is a leap year?

What is the probability that a leap year has 52 Mondays?

What is the probability that a leap year has 53 Sundays and 53 Mondays?

What is the probability that a leap year has 53 Tuesdays and 53 Mondays?

What is the probability that a leap year selected at random contains 53 Sunday?

Find the probability of 53 Mondays in a leap year.

Find the probability that a leap year, selected at random, will contain 53 Sundays.

Find the probability that a leap year, selected at random, will contain 53 Sundays.