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If the squares of a 8 xx 8 chess board ...

If the squares of a `8 xx 8` chess board are painted either red and black at random .The probability that not all squares is any alternating in colour is

A

`1//2^(64)`

B

1-`1//2^(63)`

C

`1//2`

D

none of these

Text Solution

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The correct Answer is:
To solve the problem of finding the probability that not all squares of an 8x8 chessboard are alternating in color when painted randomly red or black, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Chessboard Configuration**: - An 8x8 chessboard consists of 64 squares. - Each square can be painted either red or black. 2. **Total Possible Colorings**: - Since each of the 64 squares can be painted in 2 different colors (red or black), the total number of ways to paint the chessboard is: \[ \text{Total Outcomes} = 2^{64} \] 3. **Favorable Outcomes for Alternating Colors**: - An alternating color pattern means that no two adjacent squares can be of the same color. There are two possible alternating patterns: - Pattern 1: Starting with Red (R): - R B R B R B R B - B R B R B R B R - Pattern 2: Starting with Black (B): - B R B R B R B R - R B R B R B R B - Thus, there are 2 favorable outcomes for the chessboard to be painted in an alternating color pattern. 4. **Calculating the Probability of Alternating Colors**: - The probability \( P \) that all squares are in an alternating color pattern is given by: \[ P(\text{alternating}) = \frac{\text{Number of Favorable Outcomes}}{\text{Total Outcomes}} = \frac{2}{2^{64}} = \frac{1}{2^{63}} \] 5. **Finding the Probability of Not All Squares Being Alternating**: - The probability that not all squares are in an alternating color pattern is the complement of the probability that they are in an alternating pattern: \[ P(\text{not alternating}) = 1 - P(\text{alternating}) = 1 - \frac{1}{2^{63}} \] 6. **Final Result**: - Therefore, the probability that not all squares are in an alternating color is: \[ P(\text{not alternating}) = 1 - \frac{1}{2^{63}} \] ### Summary of the Solution: The final answer is: \[ P(\text{not alternating}) = 1 - \frac{1}{2^{63}} \]

To solve the problem of finding the probability that not all squares of an 8x8 chessboard are alternating in color when painted randomly red or black, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Chessboard Configuration**: - An 8x8 chessboard consists of 64 squares. - Each square can be painted either red or black. ...
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