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There are two red, two blue, two white, and certain number (greater than 0) of green socks n a drawer. If two socks are taken at random from the drawer4 without replacement, the probability that they are of the same color is 1/5, then the number of green socks are ________.

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To solve the problem step by step, we will follow the outlined reasoning from the video transcript. ### Step 1: Define Variables Let \( x \) be the number of green socks in the drawer. We know that there are: - 2 red socks - 2 blue socks - 2 white socks - \( x \) green socks ### Step 2: Calculate Total Number of Socks The total number of socks in the drawer is: \[ \text{Total socks} = 2 \text{ (red)} + 2 \text{ (blue)} + 2 \text{ (white)} + x \text{ (green)} = 6 + x \] ### Step 3: Calculate Total Outcomes When we draw 2 socks from \( 6 + x \) socks, the total number of ways to choose 2 socks is given by the combination formula: \[ \text{Total outcomes} = \binom{6+x}{2} = \frac{(6+x)(5+x)}{2} \] ### Step 4: Calculate Favorable Outcomes The favorable outcomes for drawing 2 socks of the same color can be calculated as follows: 1. For red socks: \( \binom{2}{2} = 1 \) 2. For blue socks: \( \binom{2}{2} = 1 \) 3. For white socks: \( \binom{2}{2} = 1 \) 4. For green socks: \( \binom{x}{2} = \frac{x(x-1)}{2} \) Thus, the total favorable outcomes are: \[ \text{Favorable outcomes} = 1 + 1 + 1 + \frac{x(x-1)}{2} = 3 + \frac{x(x-1)}{2} \] ### Step 5: Set Up the Probability Equation According to the problem, the probability of drawing two socks of the same color is given as \( \frac{1}{5} \). Therefore, we can set up the equation: \[ \frac{\text{Favorable outcomes}}{\text{Total outcomes}} = \frac{1}{5} \] This gives us: \[ \frac{3 + \frac{x(x-1)}{2}}{\frac{(6+x)(5+x)}{2}} = \frac{1}{5} \] ### Step 6: Cross Multiply to Solve for \( x \) Cross multiplying gives us: \[ 5 \left(3 + \frac{x(x-1)}{2}\right) = (6+x)(5+x) \] Expanding both sides: \[ 15 + \frac{5x(x-1)}{2} = 30 + 11x + x^2 \] ### Step 7: Eliminate the Fraction To eliminate the fraction, multiply the entire equation by 2: \[ 30 + 5x(x-1) = 60 + 22x + 2x^2 \] This simplifies to: \[ 30 + 5x^2 - 5x = 60 + 22x + 2x^2 \] ### Step 8: Rearrange the Equation Rearranging gives: \[ 5x^2 - 2x^2 - 5x - 22x + 30 - 60 = 0 \] This simplifies to: \[ 3x^2 - 27x - 30 = 0 \] ### Step 9: Factor or Use Quadratic Formula We can simplify this equation: \[ x^2 - 9x - 10 = 0 \] Factoring gives: \[ (x - 10)(x + 1) = 0 \] Thus, \( x = 10 \) or \( x = -1 \). Since \( x \) must be greater than 0, we have: \[ x = 10 \] ### Conclusion The number of green socks is \( \boxed{10} \).

To solve the problem step by step, we will follow the outlined reasoning from the video transcript. ### Step 1: Define Variables Let \( x \) be the number of green socks in the drawer. We know that there are: - 2 red socks - 2 blue socks - 2 white socks - \( x \) green socks ...
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