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Consider a pair of perpendicular straigh...

Consider a pair of perpendicular straight lines `ax^(2)+3xy-2y^(2)-5x+5y+c=0`.
The value of c is

A

-3

B

3

C

-1

D

1

Text Solution

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The correct Answer is:
To find the value of \( c \) in the equation of the pair of perpendicular straight lines given by \[ ax^2 + 3xy - 2y^2 - 5x + 5y + c = 0, \] we will follow these steps: ### Step 1: Identify coefficients From the given equation, we can identify the coefficients: - \( a = a \) - \( b = 3 \) - \( c = -2 \) - \( d = -5 \) - \( e = 5 \) - \( f = c \) ### Step 2: Use the condition for perpendicular lines For the lines to be perpendicular, the condition is: \[ a + b = 0. \] Here, \( b = -2 \). Thus, we have: \[ a + (-2) = 0 \implies a = 2. \] ### Step 3: Set up the determinant condition The determinant \( \Delta \) for the pair of straight lines must be equal to zero: \[ \Delta = abc + 2fgh - af^2 - bg^2 - ch^2 = 0. \] Substituting the known values: - \( a = 2 \) - \( b = -2 \) - \( c = c \) - \( f = \frac{5}{2} \) - \( g = -\frac{5}{2} \) - \( h = \frac{3}{2} \) ### Step 4: Substitute values into the determinant equation Now, substituting these values into the determinant equation: \[ \Delta = (2)(-2)(c) + 2\left(\frac{5}{2}\right)\left(-\frac{5}{2}\right)\left(\frac{3}{2}\right) - (2)\left(\frac{5}{2}\right)^2 - (-2)\left(-\frac{5}{2}\right)^2 - c\left(\frac{3}{2}\right)^2 = 0. \] ### Step 5: Simplify the equation Calculating each term: 1. \( (2)(-2)(c) = -4c \) 2. \( 2\left(\frac{5}{2}\right)\left(-\frac{5}{2}\right)\left(\frac{3}{2}\right) = 2 \cdot \frac{-25}{4} \cdot \frac{3}{2} = -\frac{75}{4} \) 3. \( - (2)\left(\frac{5}{2}\right)^2 = -2 \cdot \frac{25}{4} = -\frac{50}{4} \) 4. \( - (-2)\left(-\frac{5}{2}\right)^2 = -2 \cdot \frac{25}{4} = -\frac{50}{4} \) 5. \( -c\left(\frac{3}{2}\right)^2 = -c \cdot \frac{9}{4} \) Putting it all together: \[ -4c - \frac{75}{4} - \frac{50}{4} - \frac{50}{4} - \frac{9c}{4} = 0. \] ### Step 6: Combine like terms Combine the constants and the terms with \( c \): \[ -4c - \frac{75 + 50 + 50}{4} - \frac{9c}{4} = 0. \] This simplifies to: \[ -4c - \frac{175}{4} - \frac{9c}{4} = 0. \] ### Step 7: Multiply through by 4 to eliminate the fraction Multiplying the entire equation by 4 gives: \[ -16c - 175 - 9c = 0. \] ### Step 8: Combine \( c \) terms Combine the \( c \) terms: \[ -25c - 175 = 0. \] ### Step 9: Solve for \( c \) Solving for \( c \): \[ -25c = 175 \implies c = -\frac{175}{25} = -7. \] Thus, the value of \( c \) is \[ \boxed{-7}. \]

To find the value of \( c \) in the equation of the pair of perpendicular straight lines given by \[ ax^2 + 3xy - 2y^2 - 5x + 5y + c = 0, \] we will follow these steps: ...
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