Home
Class 12
MATHS
If O be the origin and the coordinate...

If O be the origin and the coordinates of P be`(1," "2," "" "3)` , then find the equation of the plane passing through P and perpendicular to OP.

Text Solution

Verified by Experts

Since `P(1, 2, -3)` is the foot of the perpendicular from the origin to the plane , OP is normal to the plane.
Thus, the direction ratios of normal to the plane are 1, 2 and -3.
Now, since the plane passes through ( 1, 2, -3), its equation is given by
`" "1(x-1)+2(y-2)-3(z+3)=0`
or `" "x+2y-3z-14=0`
Promotional Banner

Topper's Solved these Questions

  • THREE-DIMENSIONAL GEOMETRY

    CENGAGE ENGLISH|Exercise CONCEPT APPLICATION EXERCISE 3.1|12 Videos
  • THREE-DIMENSIONAL GEOMETRY

    CENGAGE ENGLISH|Exercise CONCEPT APPLICATION EXERCISE 3.2|15 Videos
  • THREE DIMENSIONAL GEOMETRY

    CENGAGE ENGLISH|Exercise All Questions|294 Videos
  • TRIGONOMETRIC EQUATIONS

    CENGAGE ENGLISH|Exercise Archives (Matrix Match Type)|1 Videos

Similar Questions

Explore conceptually related problems

The foot of the perpendicular drawn from the origin to a plane is (1,2,-3)dot Find the equation of the plane. or If O is the origin and the coordinates of P is (1,2,-3), then find the equation of the plane passing through P and perpendicular to O Pdot

Equation of plane passing through P(a,b,c) and parallel to xy plane is

If O is the origin and the coordinates of A are (a ,b , c) . Find the direction cosines of O A and the equation of the plane through A at right angles to OA.

If O is the origin and the coordinates of A are (a ,b , c) . Find the direction cosines of O A and the equation of the plane through A at right angles to OA.

The direction cosines of the line passing through P(2,3,-1) and the origin are

Equations of the line passing through (1,1,1) and perpendicular to the plane 2x+3y+z+5=0 are

Find the equation of the plane passing through the points (-1,1,1) and (1,-1,1) and perpendicular to the plane x+2y+2z=5.

Find the equation of the plane passing through the points (-1,1,1) and (1,-1,1) and perpendicular to the plane x+2y+2z=5.

Equation of a line passing through (-1,2,-3) and perpendicular to the plane 2x+3y+z+5=0 is

The equation of line passing through (2, 3, -1) and perpendicular to the plane 2x + y - 5z = 12