Show that the line of intersection of the planes `vecr*(hati+2hatj+3hatk)=0 and vecr*(3hati+2hatj+hatk)=0` is equally inclined to `hati and hatk`. Also find the angleit makes with `hatj`.

Explanation

To solve the problem step-by-step, we will first find the direction of the line of intersection of the two given planes, and then show that this line is equally inclined to the unit vectors \( \hat{i} \) and \( \hat{k} \). Finally, we will calculate the angle that this line makes with the unit vector \( \hat{j} \).

### Step 1: Identify the Normal Vectors of the Planes

The equations of the planes are given as:
1. \( \vec{r} \cdot (\hat{i} + 2\hat{j} + 3\hat{k}) = 0 \)
2. \( \vec{r} \cdot (3\hat{i} + 2\hat{j} + \hat{k}) = 0 \)

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