Find the equation of the plane which parallel to the lines `vecr=hati+hatj+lamda(2hati+hatj+4hatk) and (x+1)/(-3)=(y-3)/2=(z+2)/(1)` and is passing through the point (0, 1, -1).

Explanation

To find the equation of the plane that is parallel to the given lines and passes through the point (0, 1, -1), we will follow these steps:

### Step 1: Identify Direction Vectors
The first line is given in parametric form:
\[ \vec{r} = \hat{i} + \hat{j} + \lambda(2\hat{i} + \hat{j} + 4\hat{k}) \]
From this, we can extract the direction vector \( \vec{a} = 2\hat{i} + \hat{j} + 4\hat{k} \).
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