Find the angle between the lines `x-3y-4=0,4y-z+5=0a n dx+3y-11=0,2y=z+6=0.`

Explanation

To find the angle between the lines represented by the given equations, we will follow these steps:

### Step 1: Identify the planes and their normal vectors
The equations of the lines can be derived from the given equations of the planes. The equations are:
1. \( x - 3y - 4 = 0 \) (Plane 1)
2. \( 4y - z + 5 = 0 \) (Plane 2)
3. \( x + 3y - 11 = 0 \) (Plane 3)
4. \( 2y - z + 6 = 0 \) (Plane 4)
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