Find the angle between the line `vecr=(hati+2hatj-hatk)+lamda(hati-hatj+hatk)` and the plane `ver.(2hati-hatj+hatk)=4`

Explanation

To find the angle between the line given by the vector equation \(\vec{r} = \hat{i} + 2\hat{j} - \hat{k} + \lambda(\hat{i} - \hat{j} + \hat{k})\) and the plane defined by the equation \(\vec{r} \cdot (2\hat{i} - \hat{j} + \hat{k}) = 4\), we can follow these steps:

### Step 1: Identify the direction vector of the line
The direction vector \(\vec{b}\) of the line can be extracted from the equation:
\[ \vec{b} = \hat{i} - \hat{j} + \hat{k} \]

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