Find the equation of the plane which contains the line of intersection of the planes `vecr.(hati+2hatj+3hatk)-4=0, vecr.(2hati+hatj-hatk)+5=0` and which is perpendicular to the plane `vecr.(5hati+3hatj-6hatk)+8=0`

Explanation

To find the equation of the plane that contains the line of intersection of the given planes and is perpendicular to another plane, we can follow these steps:

### Step 1: Identify the equations of the given planes
The equations of the two planes are:
1. \( P_1: \vec{r} \cdot (\hat{i} + 2\hat{j} + 3\hat{k}) - 4 = 0 \)
2. \( P_2: \vec{r} \cdot (2\hat{i} + \hat{j} - \hat{k}) + 5 = 0 \)

### Step 2: Write the general equation of the plane containing the line of intersection
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