Find the equation of the plane passing through the straight line `(x-1)/2=(y+2)/(-3)=z/5` and perpendicular to the plane `x-y+z+2=0.`

Explanation

To find the equation of the plane that passes through the given straight line and is perpendicular to the given plane, we can follow these steps:

### Step 1: Identify the line and the plane
The line is given in the symmetric form:
\[ \frac{x-1}{2} = \frac{y+2}{-3} = \frac{z}{5} \]
This can be rewritten in parametric form:
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