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Find the radius of the circular section ...

Find the radius of the circular section in which the sphere `|vecr|=5` is cut by the plane `vecr*(hati+hatj+hatk)=3sqrt(3)`

Text Solution

Verified by Experts

The radius of the sphere is 5
The given plane is `x+y-z= 4sqrt(3)`
The length of the perpendicular from the centre (0, 0, 0) of the sphere on the plane `= (4sqrt(3))/(sqrt(1+1+1))= 4`.
Hence, radius of the circular section is `sqrt(25-16) = sqrt9 = 3 `
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