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Find the equation of a straight line in ...

Find the equation of a straight line in the plane `vecr.vecn=d` which is parallel to `vecr.vecn=d("where "vecn.vecb=0)`.

A

`vecr=veca+((d-veca.vecn)/(n^(2)))vecn+lamdavecb`

B

`vecr=veca+((d-veca.vecn)/(n))vecn+lamdavecb`

C

`vecr=veca+((veca.vecn-d)/(n^(2)))vecn+lamdavecb`

D

`vecr=veca+((veca.vecn-d)/(n))vecn+lamdavecb`

Text Solution

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The correct Answer is:
To find the equation of a straight line in the plane defined by the equation \(\vec{r} \cdot \vec{n} = d\) that is parallel to another line represented by \(\vec{r} = \vec{a} + \lambda \vec{b}\) (where \(\vec{n} \cdot \vec{b} = 0\)), we can follow these steps: ### Step 1: Identify the Plane and the Direction Vector The plane is given by the equation \(\vec{r} \cdot \vec{n} = d\). The direction vector of the line we want to find is \(\vec{b}\), and it is stated that \(\vec{n} \cdot \vec{b} = 0\), meaning that \(\vec{b}\) is perpendicular to the normal vector \(\vec{n}\) of the plane. ### Step 2: Find the Foot of the Perpendicular To find the foot of the perpendicular from the point with position vector \(\vec{a}\) to the plane, we can use the formula: \[ \vec{P} = \vec{a} - \frac{\vec{a} \cdot \vec{n} - d}{\|\vec{n}\|^2} \vec{n} \] This gives us the position vector \(\vec{P}\) of the foot of the perpendicular. ### Step 3: Write the Equation of the Line The line we are looking for will pass through the point \(\vec{P}\) and will be parallel to the direction vector \(\vec{b}\). Therefore, the equation of the line can be expressed as: \[ \vec{r} = \vec{P} + \lambda \vec{b} \] Substituting \(\vec{P}\) from Step 2, we have: \[ \vec{r} = \left(\vec{a} - \frac{\vec{a} \cdot \vec{n} - d}{\|\vec{n}\|^2} \vec{n}\right) + \lambda \vec{b} \] ### Step 4: Simplify the Equation Combining the terms, we can express the equation of the line as: \[ \vec{r} = \vec{a} + \lambda \vec{b} - \frac{\vec{a} \cdot \vec{n} - d}{\|\vec{n}\|^2} \vec{n} \] ### Final Result Thus, the equation of the straight line in the plane \(\vec{r} \cdot \vec{n} = d\) that is parallel to \(\vec{r} = \vec{a} + \lambda \vec{b}\) is: \[ \vec{r} = \vec{a} + \lambda \vec{b} - \frac{\vec{a} \cdot \vec{n} - d}{\|\vec{n}\|^2} \vec{n} \]

To find the equation of a straight line in the plane defined by the equation \(\vec{r} \cdot \vec{n} = d\) that is parallel to another line represented by \(\vec{r} = \vec{a} + \lambda \vec{b}\) (where \(\vec{n} \cdot \vec{b} = 0\)), we can follow these steps: ### Step 1: Identify the Plane and the Direction Vector The plane is given by the equation \(\vec{r} \cdot \vec{n} = d\). The direction vector of the line we want to find is \(\vec{b}\), and it is stated that \(\vec{n} \cdot \vec{b} = 0\), meaning that \(\vec{b}\) is perpendicular to the normal vector \(\vec{n}\) of the plane. ### Step 2: Find the Foot of the Perpendicular To find the foot of the perpendicular from the point with position vector \(\vec{a}\) to the plane, we can use the formula: \[ ...
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