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A rod of length 2 units whose one ends i...

A rod of length 2 units whose one ends is `(1, 0, -1)` and other end touches the plane `x-2y+ 2z+4=0`, then which statement is false

A

the rod sweeps the figure whose volume is `pi` cubic units.

B

the area of the region which the rod traces on the plane is `2pi`.

C

the length of projection of the rod on the plane is `sqrt3` units.

D

the centre of the region which the rod traces on the plane is `((2)/(3), (2)/(3), (-5)/(3))`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to analyze the given information and find out which statement is false regarding the rod and the plane. ### Step 1: Understand the Problem We have a rod of length 2 units with one end at the point \( A(1, 0, -1) \) and the other end touching the plane defined by the equation \( x - 2y + 2z + 4 = 0 \). ### Step 2: Find the Distance from Point A to the Plane To find the distance \( d \) from the point \( A(1, 0, -1) \) to the plane \( x - 2y + 2z + 4 = 0 \), we use the distance formula from a point to a plane: \[ d = \frac{|Ax_1 + By_1 + Cz_1 + D|}{\sqrt{A^2 + B^2 + C^2}} \] Where \( A = 1, B = -2, C = 2, D = 4 \) and \( (x_1, y_1, z_1) = (1, 0, -1) \). Substituting the values: \[ d = \frac{|1(1) + (-2)(0) + 2(-1) + 4|}{\sqrt{1^2 + (-2)^2 + 2^2}} \] \[ = \frac{|1 + 0 - 2 + 4|}{\sqrt{1 + 4 + 4}} = \frac{|3|}{\sqrt{9}} = \frac{3}{3} = 1 \] ### Step 3: Determine the Position of the Other End of the Rod Since the rod is 2 units long and one end is at point \( A(1, 0, -1) \), the other end \( B(x, y, z) \) must be 1 unit away from point \( A \) in the direction perpendicular to the plane. ### Step 4: Find the Radius of the Cylinder Swept by the Rod The radius \( r \) of the cylinder formed by the rod can be found using the Pythagorean theorem. The length of the rod is the hypotenuse, and the distance from point \( A \) to the plane is one leg of the triangle. Let \( h \) be the height (distance to the plane) and \( r \) be the radius: \[ \text{Length of the rod}^2 = r^2 + h^2 \] \[ 2^2 = r^2 + 1^2 \] \[ 4 = r^2 + 1 \implies r^2 = 3 \implies r = \sqrt{3} \] ### Step 5: Calculate the Volume of the Cylinder The volume \( V \) of the cylinder swept by the rod is given by: \[ V = \pi r^2 h \] Substituting \( r^2 = 3 \) and \( h = 1 \): \[ V = \pi \cdot 3 \cdot 1 = 3\pi \] ### Step 6: Check Each Statement 1. **Statement A**: The volume is \( \pi \) cubic units. **(False)** 2. **Statement B**: The area of the region traced by the rod on the plane is \( 2\pi \). **(False)** 3. **Statement C**: The length of the projection of the rod on the plane is \( \sqrt{3} \). **(True)** 4. **Statement D**: The center of the region traced by the rod on the plane is at \( (1, 0, -1) \). **(True)** ### Conclusion The false statements are A and B. However, since the question asks for which statement is false, we can conclude that: **The false statement is:** The volume of the rod is \( \pi \) cubic units.

To solve the problem step by step, we need to analyze the given information and find out which statement is false regarding the rod and the plane. ### Step 1: Understand the Problem We have a rod of length 2 units with one end at the point \( A(1, 0, -1) \) and the other end touching the plane defined by the equation \( x - 2y + 2z + 4 = 0 \). ### Step 2: Find the Distance from Point A to the Plane To find the distance \( d \) from the point \( A(1, 0, -1) \) to the plane \( x - 2y + 2z + 4 = 0 \), we use the distance formula from a point to a plane: ...
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